Q1: cos θ = 8.4/15.2 → θ = cos⁻¹(8.4/15.2) = 56.45°
Q2: tan θ = 7.3/12.5 → θ = tan⁻¹(7.3/12.5) = 30.28°
Q3: cos A = 6.2/9.7 → A = cos⁻¹(6.2/9.7) = 50.27°
Q4: sin B = 5.8/11.3 → B = sin⁻¹(5.8/11.3) = 30.88°
Q5: cos 35° = 14.2/x → x = 14.2/cos 35° = 17.33 cm
Q6: tan 48° = y/9.6 → y = 9.6 × tan 48° = 10.66 cm
Q7: tan 22° = 4.5/z → z = 4.5/tan 22° = 11.14 cm
Q8: sin 63° = a/17.8 → a = 17.8 × sin 63° = 15.86 cm
Q9: cos 15° = b/23.1 → b = 23.1 × cos 15° = 22.31 cm
Q10: sin 52° = 11.4/c → c = 11.4/sin 52° = 14.47 cm
Q11: sin θ = 9.1/16.5 → θ = sin⁻¹(9.1/16.5) = 33.47°
Q12: tan 37° = d/10.3 → d = 10.3 × tan 37° = 7.76 cm
Q13: tan φ = 3.8/5.5 → φ = tan⁻¹(3.8/5.5) = 34.64°
Q14: cos 28° = e/13.7 → e = 13.7 × cos 28° = 12.10 cm
Q15: sin 41° = 7.6/f → f = 7.6/sin 41° = 11.58 cm
Q16: cos θ = 11.5/14.2 → θ = cos⁻¹(11.5/14.2) = 35.92°
Q17: tan α = 22/35 → α = tan⁻¹(22/35) = 32.15°
Q18: Half-width = 6 m. tan θ = 4.5/6 → θ = tan⁻¹(4.5/6) = 36.87°
Q19: tan 38° = 1.7/s → s = 1.7/tan 38° = 2.18 m
Q20: sin 55° = h/65 → h = 65 × sin 55° = 53.24 m
Q21: sin 8.5° = h/250 → h = 250 × sin 8.5° = 36.95 m
Q22: Height diff = 3.2 − 1.6 = 1.6 m. tan 42° = 1.6/d → d = 1.6/tan 42° = 1.78 m
Q23(a): θ = sin⁻¹(0.63) = 39.06°
Q23(b): opp = 18.4 × 0.63 = 11.59 cm
Q23(c): adj = √(18.4² − 11.59²) = 14.19 cm
Q24: opp = 22.3 × sin 57° = 18.69 cm. Area = ½ × 14.6 × 18.69 = 136.53 cm²
Q25(a): 18 × cos 45° = 12.73 km north
Q25(b): 18 × sin 45° + 24 = 36.73 km east
Q25(c): √(12.73² + 36.73²) = 38.87 km
Q26: tan 28° = 45/d → d = 45/tan 28° = 84.63 m
Q27(a): Pole height = 8.5 − 1.2 = 7.3 m. sin 62° = 7.3/cable → cable = 8.27 m
Q27(b): tan 62° = 7.3/d → d = 7.3/tan 62° = 3.88 m
Q27(c): tan θ = 8.5/6 → θ = 54.78°
Q28: tan 35° = h/24 → h = 24 × tan 35° = 16.80 m
Q29: d = √(12.5² − 10²) = √(156.25 − 100) = √56.25 = 7.50 m
Q30(a): h = 3.6 × sin 18° = 1.11 m
Q30(b): d = 3.6 × cos 18° = 3.42 m
Q31: Let B to tower = x. tan 52° = h/x, tan 30° = h/(x+40). Solving: x = 32.87 m. h = 32.87 × tan 52° = 42.07 m
Q32(a): Slant height = √(12² + 5²) = √169 = 13.00 m
Q32(b): Half-diagonal = √(5²+5²) = 7.07 m. tan θ = 12/7.07 → θ = 59.49°
Q33: Let 2nd position distance = x. tan 40° = h/x, tan 25° = h/(x+30). Solving: x = 37.53 m. h above eye = 31.49 m. Window = 31.49 + 1.5 = 32.99 m
Q34: Let left distance = x. tan 40° = h/x, tan 55° = h/(18−x). Solving: x = 11.34 m. h = 11.34 × tan 40° = 9.51 m
Q35: Floor diagonal = √(8² + 6²) = 10 m. Space diagonal = √(10² + 5²) = √125 = 11.18 m
Q36(a): tan 32° = h/42 → h = 42 × tan 32° = 26.24 m
Q36(b): Total horizontal = 42 + 15 = 57 m. Wire = √(26.24² + 57²) = 62.75 m